Free Mathematics Exam Questions and Answers SS3 These Mathematics questions and answers were pulled from our book (Mathematics questions for SS3); Compiled to serve as a reference material to help teachers draw up test and exam questions faster. It could also help students assess their level of exam preparation. Each sample question includes correct answers. […]
Free Mathematics Exam Questions and Answers SS3
These Mathematics questions and answers were pulled from our book (Mathematics questions for SS3); Compiled to serve as a reference material to help teachers draw up test and exam questions faster. It could also help students assess their level of exam preparation. Each sample question includes correct answers.
The Questions are based on the current NERDC curriculum (UBE compliant) Sample Mathematics Exam Questions and Answers
ARITHMETIC AND GEOMETRIC PROGRESSION
1. Johnbull bought an electronic gadget worth ₦208,000. He pays half the worth and agrees to pay the remaining in five instalments with a compound interest of 6% per annum, calculate the annual instalment to the nearest naira.
A. ₦ 26,300
B. ₦ 25.428
C. ₦ 14,380
D. ₦ 24,700
See the Answer
The correct answer is D
Explanation:
Worth of item = ₦ 208,000. Amount paid = ₦ half the worth = 208,000 1/2 = 104,000.
Balance = 104,000 [1 + (6/100)]5 = [a (1.065 – 1)]/[1.06 – 1]; 104,000 [1.06]5
= [a (1.065 – 1)]/0.06, therefore, a = [104,000 (1.06)5 0.06]/[1.065 – 1] = ₦ 24,700
2. Calculate the amount arising from annuity of ₦ 750 annually payable in 10 years, if the compund interest payable is at 7% per annum.
A. ₦ 10,363
B. ₦ 9,384
C. ₦ 40,040
D. ₦ 25,313
See the Answer
The correct answer is A
Explanation:
Annual annuity = ₦ 750, time payable
= 10 years, rate = 7% = 0.07 + 1 = 1.07
Amount = [₦ 750(1.0710 – 1)] [1.07 – 1] = ₦ 10,362.9 ₦ 10,363
3. Find the amount an annuity of ₦200 payable for 11years at 10% per annum interest.
A. ₦ 7065
B. ₦ 6053
C. ₦ 3706
D. ₦ 1200
See the Answer
The correct answer is C
Explanation:
Using the equation S =
[a (rn – 1)]/[r – 1], where a = ₦ 200, r = 1.1, n = 11.
CHANGE OF SUBJECT FORMULA
1. Make B the subject of formula: A = [2B + C]/[2BC].
A. B = C/[2A2C – 2]
B. B = C/[2A2C + 2]
C. B = 1/[CA2 + 2]
D. B = 1/[2A2C + 2]
See the Answer
The correct answer is A
Explanation:
A = [2B + C]/[2BC];
A2 = [2B + C]/[2BC];
2A2BC = 2B + C;
C = 2A2BC – 2B;
C = B[2A2C – 2];
B = C/[2A2C – 2]
2. Given that A = [12/C – B/3], make C the subject of formula.
A. C = [3A2 + B]/36
B. C = 36/[3A2 + B]
C. C = [36B]/[3A2]
D. C = [3A3 – B]/36
See the Answer
The correct answer is B
Explanation:
A = [12/C – B/3];
A2 = 12/C – B/3 = [36 – BC]/3C;
3CA2 = 36 – BC;
36 = 3CA2 + BC;
36 = C[3A2 + B];
C = 36/[3A2 + B]
3. WX + WY + 7/Z = 3, make Y the subject.
A. [3Z – 7 – ZWX]/ZW
B. [7Z – 3 + ZWX]/ZX
C. [ZX – ZWX + 7]/WX
D. [WX + 7Z – ZW]/ZX
See the Answer
The correct answer is A
Explanation:
WX + WY + 7/Z = 3;
[ZWX + ZWY + 7]/Z = 3;
ZWX + ZWY +7 = 3Z; ZWY = 3Z – 7 – ZWX;
Y = [3Z – 7 – ZWX]/ZW
4. Make P the subject: R = [Q2 – PR]/[Q + P].
A. P = [Q(Q – R)]/2R
B. P = [2R(Q2 – Q)]/R
C. P = [2R(1 – Q2)]/Q
D. P = [2Q(R – Q)]/RQ
See the Answer
The correct answer is A
Explanation:
R = [Q – PR]/[Q + P]; R[Q + P] = Q2 – PR;
RQ + RP = Q2 – PR; RQ = Q2 – PR – RP;
RQ = Q2 -2PR; 2PR = Q2 – RQ;
P = [Q2 – RQ]/2R = [Q(Q – R)]/2R
5. Make g the subject of formula from the equation t/L = [(42)/g].
A. g = [43L]/t.
B. g = [4]/[tL]
C. g = [42L2]/t2
D. g = [4L2]/t2
See the Answer
The correct answer is C
Explanation:
t/L = [(42)/g], square both sides of the equation,
then, t2/L2 = [42]/g;
gt2 = 42L2;
g =[42L2]/t2.
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EQUATIONS AND FORMULAE
1. One stick is 9cm longer than another, 25 of the longer stick is equal to 12 of the shorter stick. Find the length of the longer stick.
A. 45 cm
B. 36 cm
C. 27 cm
D. 54 cm
See the Answer
The correct answer is A
Explanation:
Let the shorter stick be n;
2/5[n + 9] = n/2 2 2[n + 9] = 5n;
4n + 36 = 5n 5n – 4n = 36,
therefore, n = 36cm.
The longer stick is 36 + 9 = 45cm
2. The result of adding 3 to x and multiplying the answer by 4 is the same as taking 3 from five times x. Find the value of x.
A. 27
B. 6
C. 15
D. -15
See the Answer
The correct answer is C
Explanation:
4[x + 3] = 5x – 3;
4x + 12 = 5x – 3 5x – 4x = 12 + 3;
x = 15.
3. Somina and Qiana share 191 naira between them so that Qiana get 27 naira less than Somina. Find how much money each gets.
A. ₦ 109; ₦ 82
B. ₦ 109; ₦ 136
C. ₦ 136; ₦ 82
D. ₦ 218; ₦ 191
See the Answer
The correct answer is A
Explanation:
Let Somina’s share be represented by x;
Qiana receives x – 27; x + x – 27 = 191 2x – 27 = 191; 2x = 191 + 27; 2x = 218.
Therefore, x = 218/2 = ₦ 109.
Qiana’s share = 109 – 27 = ₦ 82.
The answer is ₦ 109 ; ₦ 82
4. The sum of 8 and one-fourth of n is one more than twice n. Find the value of n.
A. -12
B. 4
C. -312
D. 8
See the Answer
The correct answer is B
Explanation:
8 + n/4 = 2n + 1;
multiply through by 4;
32 + n = 8n + 4 8n – n = 32 – 4 7n = 28.
Therefore, n = 28/7 = 4.
5. A rectangle is one-third as long as it is wide. If its perimeter is 120cm, find the width of the rectangle.
A. 15cm
B. 20cm
C. 30cm
D. 45cm
See the Answer
The correct answer is D
Explanation:
Perimeter of a quadrilateral shape = 2[L + B],
where B = Breadth, L = length = B/3,
Perimeter = 120 2[B/3 + B] = 120;
B/3 + B = 120/2 = 60 B + 3B/3 = 60;
B + 3B = 60 3 4B = 180;
B = 180/4
= 45cm
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