Mathematics Exam Questions and Answers for SS2

These Mathematics questions and answers were pulled from our book (Mathematics questions for ss2); Compiled to serve as a reference material to help teachers draw up test and exam questions faster. It could also help students assess their level of exam preparation. Each sample question includes correct answers.

The Questions are based on the current NERDC curriculum (UBE compliant)

Sample Mathematics Exam Questions and Answers

ARITHMETIC AND GEOMETRIC PROGRESSION
DIRECTION: Choose the correct answer from the lettered options.
1. Find the number of term of the sequence that will make up 240. The given sequence are 13, 16, 19, 22, ……………
A. 9
B. 17
C. 27
D. 29

See the Answer

The correct answer is A

Explanation: Hint [The question forms A.P.]. Using the equation Sn = [n  2a + (n – 1) d]/2, where a = 13, d = 3, Sn = 240. Solve using the formula given .

2. If the second and fourth terms of a G.P. are 8 and 32 respectively, what is the sum of the first four terms?
A. 28
B. 40
C. 48
D. 60

See the Answer

The correct answer is D

Explanation:The general form of a G.P. is a, ar, ar2,…., arn – 1 (for n terms).
Here ar =second term = 8; ar3 = fourth term = 32. [ar3/ar = r2] 32/8 = 4 = r2 (r = (4 = 2 (where r=common ratio, a = 1st term).
For ar = 8
2a = 8
a = 4
For r >1, sum =
a[rn – 1]/r – 1,
where n = 4, r = 2, a = 4.

Then 4[24 – 1]/2 – 1 = 4 x 15/1 = 60.
.

3. Calculate the sum of the tenth terms of the G.P. 5, -21⁄2, 11⁄4 ……………
A. 4.77
B. 3.34
C. 6.852
D. 11.27

See the Answer

The correct answer is B

Expalnation:Use the equation Sn = [a  (1 – rn)]/[1 – r], since the common ratio is less than 1 and a = 5, r = -0.5, n = 10.

4. If the 8th term of an A.P. is twice the 4th term and the sum of the first 5 terms is 47, find the common difference.
A. 6.31
B. 3.13
C. 4.42
D. 2.24

See the Answer

The correct answer is B

Explanation:Un = a + [n – 1]d; U8 = 2U4; U8 = a + [n – 1]d,

where n = 8; 2U4 = 2[a + (n – 1)d], where n = 4; a + [8 – 1]d

= 2[a + (4 – 1)d]; a + 7d = 2[a + 3d]; a + 7d = 2a + 6d; 7d – 6d = 2a -a; d = a………[i];

Sn = [n  2a + (n -1 )d]/2; S5 = [5  2a + (5 – 1)d]/2 = 47; 2.5[2a + 4d]; recall that a = d,

therefore, 2d + 4d = 47/2.5; 6d = 18.8; d = 18.8/6 = 3.13.

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5. The 4th term of an A. P. is 13 while the 10th term is 31. Find the 21st term.
A. 175.
B. 85.
C. 64.
D. 45.

See the Answer

The correct answer is C

Explanation:The 4th term = a + 3d;
The 10th term = a + 9d;
a + 3d = 13 —— [i];
a + 9d = 31 —— [ii];
Subtract equation [i] from [ii] -6d = -18; d = 3;
a + 3[3] = 13;
a = 13 – 9 = 4
Therefore, the 21st term = a + 20d = 4 + 20[3] = 64.

BEARINGS
DIRECTION: Choose the correct answer from the lettered options.
1. The bearing of a point A from a point B is 042o. Calculate the bearing of B from A.
A. 228o
B. 222o
C. 138o
D. 48o

See the Answer

The correct answer is B.

2. A ladder of length 5m rests against a vertical wall and makes an angle of 60o with the ground. How far is the foot of the ladder from the wall?
A. √3/2m
B. 2 1/2m
C. 5√3/2m
D. 5m

See the Answer

The correct answer is B.

3. The angle of depression of a tree when compared to the length of its shadow on the level ground is 28o and the length of its shadow is 9.78m. What is the height of the tree?
A. 6.64m
B. 5.50m
C. 5.20m
D. 4.20m

See the Answer

The correct answer is C.

4. The bearing of a bird on a tree from a hunter on the ground is N72°E. What is the bearing of the hunter from the bird?
A. S18°W
B. S72°W
C. S72°E
D. S27°E

See the Answer

The correct answer is B.

5. An erected pole is 7cm high from the ground. It casts a shadow on the horizontal ground when the altitude of the sun is 60o. Calculate the length of the shadow.
A. 7√ m
B. 7m
C. 21m
D. 21√3m

See the Answer

The correct answer is A.

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Mathematics Exam Questions and Answers for SS2

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