Exxon Mobil Mechanical Engineering Aptitude Test Past Questions

Free Exxon Mobil Mechanical Engineering Aptitude Test Past Questions and Answers

Can you ace these Exxon Mobil Mechanical Engineering Test questions? Start honing your skills with some past questions practice and get a preview of what you can expect on test day.

We pulled these Mechanical Engineering questions from our study pack Exxonmobil job-aptitude-test past questions studypack. Each sample question includes correct answers, so you can see how to crack it!

Note about the test format: On the Exxon mobil aptitude test you’ll face 4 test sections: Numerical reasoning, Verbal reasoning, Abstract reasoning, and the Skill test section (Mechanical Engineering based questions).

1. Work input is directly proportional to heat and the constant of proportionality is called
a. joule’s equivalent
b. mechanical equivalent of heat
c. all of the mentioned
d. none of the mentioned

See the Answer
The correct answer is C

Explanation:True for a closed system undergoing a cycle.


2. The value of constant of proportionality, J, has the value
a. 1
b. 0
c. -1
d. infinity

See the Answer
The correct answer is A

Explanation:In the S.I. system, both heat and work are measured in the derived unit of energy, the Joule.


3. It was Joule who first established that heat is a form of energy, and thus laid the foundation of the first law of thermodynamics.
a. true
b. false

See the Answer
The correct answer is A

Explanation:Prior to Joule, heat was considered to be an invisible fluid flowing from a body of higher calorie to a body of lower calorie.


4. A window having area of 2m^2 has a surface temperature of 15°C and the air is blowing at 2°C across it with convection heat transfer coefficient of h = 125 W/m2K. Find the total heat transfer loss?
a. 3250 W
b. 2250 W
c. 4250 W
d. 5250 W

See the Answer
The correct answer is A

Explanation:Total heat transfer loss = h A ΔT = 125*2*(15-2) = 3250 W.


5. The sun shines on a 150 m2 road surface so it is at 45°C. Below the 5cm thick asphalt (average conductivity of 0.06 W/m K), is a layer of rubbles at 15°C. Find the rate of heat transfer to the rubbles.
a. 5300 W
b. 5400 W
c. 5500 W
d. 5600 W

See the Answer
The correct answer is B

Explanation:There is conduction through the asphalt layer. Heat transfer rate = k A ΔT/Δx = 0.06 × 150 × (45-15)/0.05 = 5400 W


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6. Thermal conductivity is defined as the heat flow per unit time
a. When temperature gradient is unity
b. Across the wall with no temperature
c. Through a unit thickness of the wall
d. Across unit area where temperature gradient is unity

See the Answer
The correct answer is D

Explanation:Thermal conductivity of a material is because of migration of free electrons and lattice vibrational waves.


7. Mark the matter with least value of thermal conductivity
a. Air
b. Water
c. Ash
d. Window glass

See the Answer
The correct answer is A

Explanation:For air it is .024 W/ m degree i.e. lowest.


8. Which one of the following forms of water have the highest value of thermal conductivity?
a. Boiling water
b. Steam
c. Solid ice
d. Melting ice

See the Answer
The correct answer is C

Explanation:For ice it is 2.25 W/m degree i.e. maximum.


9. A pot of steel (conductivity 50 W/m K), with a 5 mm thick bottom is filled with liquid water at 15°C. The pot has a radius of 10 cm and is now placed on a stove that delivers 250 Was heat transfer. Find the temperature on the outer pot bottom surface assuming the inner surface to be at 15°C.
a. 15.8°C
b. 16.8°C
c. 18.8°C
d. 19.8°C

See the Answer
The correct answer is A

Explanation: Steady conduction, Q = k A ΔT/Δx ⇒ ΔΤ = Q Δx / kΑ ΔT = 250 × 0.005/ (50 × π/4 × 0.22) = 0.796 T = 15 + 0.796 = 15.8°C.


10. A water-heater is covered with insulation boards over a total surface area of 3 m2. The inside board surface is at 75°C and the outside being at 20°C and the conductivity of material being 0.08 W/m K. Find the thickness of board to limit the heat transfer loss to 200 W ?
a. 0.036 m
b. 0.046 m
c. 0.056 m
d. 0.066 m

See the Answer
The correct answer is D

Explanation:Steady state conduction through board. Q = k A ΔT/Δx ⇒ ΔΤ = Q Δx / kΑ Δx = 0.08 × 3 × (75 − 20)/200 = 0.066 m.



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