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These Free Bayelsa civil service Past Questions and Answers contain a collection of sample past questions and answers that you can use for studying for your upcoming Bayelsa civil service exam. We pulled this Bayelsacivil service Past Questions and Answers from our study pack Bayelsa civil service Practice questions and answers
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Free Sample Bayelsa civil service Past questions and answers
ENGLISH LANGUAGE
1. I saw a woman walking (along) the road.
(A) Adverb
(B) Adjective
(C) Preposition
(D) Conjunction
ANSWER: C
2. Still waters run (deep).
(A) Adverb
(B) Adjective
(C) Preposition
(D) Conjunction
ANSWER: A
3. She (as well as) her sister is engaged.
(A) Adverb
(B) Adjective
(C) Preposition
(D) Conjunction
ANSWER: D
4. This golden ring is too (costly) to purchase.
(A) Adverb
(B) Adjective
(C) Preposition
(D) Conjunction
ANSWER: B
5. I would rather die (than) beg.
(A) Adverb
(B) Adjective
(C) Preposition
(D) Conjunction
ANSWER: D
MATHEMATICS SECTION
1. Average age of students of an adult school is 40 years. 120 new students whose average age is 32 years joined the school. As a result, the average age is decreased by 4 years. Find the number of students of the school after joining of the new students:
A. 1200
B. 120
C. 360
D. 240
E. None of the above
Solution: D
Let the no of students present currently = x
Sum of Age of all the students currently = Average Age × No. of Students
= 40x
New Students = 120
Average Age of new Students only = 32
Sum of Age of all the new Students = 32 × 120 = 3840 Now Total No. of Students = x + 120
New Average = 40 – 4 = 36
Sum of Age of Total Students = 40x + 3840
Average = Sum of Age of all the students / Total no. of students
⇒ 36 = (40x + 3840)/ (x + 120)
⇒ 36 × (x + 120) = (40x + 3840)
⇒ 36x + 4320 = 40x + 3840
⇒ 4x = 480
⇒ x = 120
Total No. of students after joining of new students = x + 120 = 120 + 120 = 240
2. A canteen requires 112 kgs. of wheat for a week. How many kgs. of wheat will it require for 69 days?
A. 1204 kgs
B. 1401 kgs
C. 1104 kgs
D. 1014 kgs
E. None of these
Solution: C
Weight required by the canteen per week or for 7 days = 112 Kgs
∴ Weight required by the canteen for 1 day = (112 / 7) = 16 Kgs
∴ Weight required by the canteen for 69 days = 16 × 69 = 1104 Kgs
3. A is driving on a highway when the police fine him for over speeding and exceeding the limit by 10 km/hr. At the same time B is fined for over speeding by
twice the amount by which A exceeded the limit. If he was driving at 35 km/hr. What is the speed limit for the road?
A. 30 km/hr
B. 15 km/hr
C. 20 km/hr
D. 16 km/hr
E. 22 km/hr
Solution: B
Say X is the speed limit of the road.
Given, B exceeded the limit by 2 times the amount by which A exceeded the limit. Also given, A exceeded the limit by 10 km/hr
⇒ B exceeded the limit by 2 × 10 = 20 km/hr
∴ Speed of B = X + 20 and it is given to be 35 km/hr
∴ X + 20 = 35
⇒ X = 35 – 20 = 15 km/hr
∴ Speed limit of the road = 15 km/hr
4. If n is the sum of two consecutive odd integers and less than 100, what is greatest possibility of n?
A. 98
B. 94
C. 96
D. 99
E. 92
Solution: C
Say (2x+1) and (2x+3) are the two consecutive odd integers for some positive integer x.
⇒ (2x+1) + (2x+3) = n
⇒ 4x + 4 = n Given n < 100
⇒ 4x+ 4 < 100
⇒ 4x < 96
⇒ x < 24
Since x is an integer and maximum possible value of x = 23. For x = 23, maximum possible value of n = 4 × 23 + 4 = 96
5. When I become as old as my father is now, I will be 5 times the age of my son now. In addition, my son will be 8 years older than what I am now. If the sum of my father’s age and my age is equal to 100. How old is my son now?
A. 12
B. 14
C. 13
D. 18
E. 22
Solution: C
Say Age of father is A years and age of my age is B years and my son’s
age is C years.
Given, sum of my and my father’s age is 100
⇒ A + B = 100 …… (Eq.1)
Also given when my I’m as old as my father is now (A – B years later), my
age is 5 times my son’s present age
⇒ A = 5 × C ……. (Eq.2)
Also after (A – B) years, my son is 8 years older than my present age
⇒ C + A – B = B + 8
⇒ A – 2B + C = 8 ……. (Eq.3)
From Eq.1 we know A = 100 – B Substituting in Eq.3
⇒ 100 – B – 2B + C =8
⇒ 3B – C = 92 ……… (Eq.4)
Substituting Eq.2 in Eq.3
⇒ 6C – 2B = 8
⇒ 3C – B = 4 (Eq.5)
Eq.4 + 3 × Eq.5
⇒ 8C = 92+12 = 104
⇒ C = 104/8 = 13 years is the present age of Son.
GENERAL KNOWLEDGE
1. Who is the current chairman of Bayelsa State Civil Service Commission?
A. Jim George Akhimien
B. Dr. Afolabi Adewakun
C. Peter Singabele
D. Governor Rotimi Akeredolu
Answer: C
2. What year was Bayelsa State created?
A. 1976
B. 1977
C. 1978
D. 1996
Answer: D
3. Nigeria is located in which part of Africa?
(A) West Africa
(B) East Africa
(C) North Africa
(D) Southern Africa
Answer: A
4. The total population of Nigeria (2020 estimate) is about
(A) 191 million
(B) 201 million
(C) 211 million
(D) 221 million
Answer: B
5. What is the name of the chairman of Federal civil service of Nigeria?
A. Folashade Mejabio Yemi-Esan CFR
B. Jim George Akhimien
C. A. Oshionebo
D. Rotimi Akeredolu
Answer: A
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