AIICO Insurance Past Questions and Answers

Our Exclusive AIICO Insurance Past Questions and Answers study pack  will help you prepare faster for recruitment test into AIICO insurance. The study pack comes with worked questions, answers, and indepth explanations on how to solve the questions.

About AIICO Insurance:

Our Exclusive AIICO Insurance Past Questions and Answers study pack  will help you prepare faster for recruitment test into AIICO insurance. The study pack comes with worked questions, answers, and indepth explanations on how to solve the questions.

AIICO Insurance Past Questions Format

AIICO insurance Aptitude Test basically covers the following areas:

• Quantitative/Numerical Reasoning
• Verbal reasoning and
• Logical Reasoning / General knowledge/Current affairs

TIMING:

• 50 Questions – 60minutes (on most occassion)

AIICO PLC Test format has not changed in the last 5-years, although questions do change. This study pack will help you prepare faster, and guarantee your success at the test.

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Sample Questions and Answers for AIICO Insurance Past Questions and Answers pack

Instructions:

Before we get started with some serious practice, it might be helpful to brush-up on some
basic math skills needed for success in the test. You may move on if your math
skills are great!

In most aptitude test calculations, you will be required to work in approximated figures,
in such cases, rounding off is required.
To round off any number:

1. Underline the place value to which you’re rounding off.
2. Look to the immediate right (one place) of your underlined place value.
3. Identify the number (the one to the right). If it is 5 or higher, round your underlined
   place value up 1. If the number (the one to the right) is 4 or less,
   leave your underlined place value as it is and change all the other numbers to
   its right to zeros.
   EXAMPLE: Round to the nearest thousandth:
   345,678 becomes 346,000. 928,499 becomes
   928,000

Fractions consist of two numbers: a numerator (which is above the line) and a
denominator
(which is below the line).
1 (numerator)
2 (denominator)
The denominator lets us know the
number of equal parts into which
something is divided.
The numerator tells us how many of
these equal parts are contained in the
fraction.
(i) Reducing Fractions
A fraction must be reduced to the lowest terms. This is done by dividing both the
numerator and the denominator by the largest number that will divide evenly into both.
For example, 14⁄16 is reduced by dividing both terms by 2, thus giving us 7⁄8.
Likewise, 20⁄25 is reduced to 4⁄5 by dividing both numerator and denominator by 5.
(ii) Adding Fractions
To add fractions, you must first change all denominators to their lowest common
denominator (LCD)—the lowest number that can be divided evenly by all the
denominators in the problem. When you have all the denominators the same, you may
add fractions by simply adding the numerators (the denominator remains the same).

(i). Changing Decimals to Percents
To change decimals to percents:

1. Move the decimal point two places to the right.
2. Insert a percent sign.
   .75 = 75% .05 = 5%
   (ii). Changing Percents to Decimals
   To change percents to decimals:
3. Eliminate the percent sign.
4. Move the decimal point two places to the left. (Sometimes adding zeros will be
   necessary.)
   75% = .75 5% = .05
   23% = .23 .2% = .002
   (iii). Changing Fractions to Percents
   To change a fraction to a percent:
5. Multiply by 100.
6. Insert a percent sign.
   1⁄2 = (1⁄2) × 100 = 100⁄2 = 50%
   2⁄5 = (2⁄5) × 100 = 200⁄5 = 40%