# ABInBev Aptitude test past questions study pack- 2023 [free]

Are you in need of a Free ABInBev Aptitude test past questions study pack- 2023? If yes, then you have just come to the right place. Past questions available for download include: These past questions will be delivered in pdf format for you as soon as you get them.

Free ABInBev Aptitude test past questions study pack- 2023 is highly mandatory because their screening is based on the candidate’s performance in the test.

**Note about Free ABInBev Aptitude test past questions study pack- 2023**

On the Free ABInBev Aptitude test past questions study pack- [2023], you’ll face 2 test sections:

- VERBAL REASONING
- NUMERICAL REASONING

### Sample Free ABInBev Aptitude test past questions study pack- [2023]

*Below are samples of Free ABInBev Aptitude test past questions study pack- [2023]*

*Select the correct answer from the following options lettered A-D*

**VERBAL REASONING**

**1.** Which of the following word is nearly most opposite in meaning to the word “BRUSQUE”?

(A) Gold

(B) Opulent

(C) Gracious

(D) Suspect

**Answer: (C)**

**2.** Which of the following is the Antonym of the word “ORNATE”?

(A) Spartan

(B) Blemished

(C) Sturdy

(D) Counterfeit

**Answer: (B)**

**3.** Which of the following is the Antonym of the word “EXTENUATE”?

(A) Alleviate

(B) Preclude

(C) Worsen

(D) Subdue

**Answer: (C)**

**4**. Which of the following is the synonym of the word “NUANCE”?

(A) New word

(B) Sense

(C) Interpretation

(D) Subtle meaning

**Answer: (D)**

**5.** Which of the following is the synonym of the word “PLUTOCRAT”?

(A) Magnate

(B) Priest

(C) Judge

(D) Astronaut

**Answer: (A)**

**6**. Which of the following is the synonym of the word “BULWARK”?

(A) Conundrum

(B) Festival

(C) Rampart

(D) Confuse

**Answer: (C)**

**NUMERICAL REASONING**

**1.** An equilateral triangle of side √3cm is inscribed in a circle. Find the radius of the circle.

A. 2/3 cm

B. 2 cm

C. 1 cm

D. 3 cm

**Answer: C**

**Explanation**

Since the inscribed triangle is equilateral, therefore the angles at all the points = 60°

Using the formula for inscribed circle,

2R = asinA=bsinB=csinC

where R = radius of the circle; a, b and c are the sides of the triangle.

⇒ 2R = 3√sin60

2R = 3√3√2

2R = 2

R = 1cm

**2.** 3y = 4x – 1 and Ky = x + 3 are equations of two straight lines. If the two lines are perpendicular to each other, find K.

A. -4/3

B. -3/4

C. 3/4

D. 4/3

**Answer: A**

**Explanation**

Grad of 3y = 4x – 1

y = 4x/3 – 1/3

Grad = 4/3

Grad of Ky = x + 3

y = x/k + 3/4

Grad = 1/k

Since two lines are perpendicular,

1/k = -3/4

-3k = 4

k = -4/3

**3.** if P and Q are fixed points and X is a point which moves so that XP = XQ, the locus of X is

A. A straight line

B. a circle

C. the bisector of angle PXQ

D. the perpendicular bisector of PQ

Answer: D

**4.** In a regular polygon, each interior angle doubles its corresponding exterior angle. Find the number of sides of the polygon.

A. 8

B. 6

C. 4

D. 3

**Answer: B**

**Explanation**

2x + x = 180°, => 3x = 180°, and thus x = 60°

Each exterior angle = 60° but size of ext. angle = 360°/n

Therefore 60° = 360°/n

n = 360°/60° = 6 sides

**5**. A predator moves in a circle of radius √2 centre (0,0), while a prey moves along the line y = x. If 0 ≤ x ≤ 2, at which point(s) will they meet?

A. (1,1) only

B. (1,1) and (1,2)

C. (0,0) and (1,1)

D. (√2,√2) only

Answer: Option A

Explanation

x2 + y2 = (√2)2

x2 + y2 = 2

but y = x

Thus; x2 + x2 = 2

2×2 = 2

x2 = + or – 1

But x2 + y2 = 2

12 + y2 = 2

1 + y2 = 2

y2 = 2 – 1

y2 = 1

y = + or – 1

Thus point (x,y) = (1,1) only.