ABInBev Aptitude test past questions study pack- 2023 [free]
Are you in need of a Free ABInBev Aptitude test past questions study pack- 2023? If yes, then you have just come to the right place. Past questions available for download include: These past questions will be delivered in pdf format for you as soon as you get them.
Free ABInBev Aptitude test past questions study pack- 2023 is highly mandatory because their screening is based on the candidate’s performance in the test.
Note about Free ABInBev Aptitude test past questions study pack- 2023
On the Free ABInBev Aptitude test past questions study pack- [2023], you’ll face 2 test sections:
- VERBAL REASONING
- NUMERICAL REASONING
Sample Free ABInBev Aptitude test past questions study pack- [2023]
Below are samples of Free ABInBev Aptitude test past questions study pack- [2023]
Select the correct answer from the following options lettered A-D
VERBAL REASONING
1. Which of the following word is nearly most opposite in meaning to the word “BRUSQUE”?
(A) Gold
(B) Opulent
(C) Gracious
(D) Suspect
Answer: (C)
2. Which of the following is the Antonym of the word “ORNATE”?
(A) Spartan
(B) Blemished
(C) Sturdy
(D) Counterfeit
Answer: (B)
3. Which of the following is the Antonym of the word “EXTENUATE”?
(A) Alleviate
(B) Preclude
(C) Worsen
(D) Subdue
Answer: (C)
4. Which of the following is the synonym of the word “NUANCE”?
(A) New word
(B) Sense
(C) Interpretation
(D) Subtle meaning
Answer: (D)
5. Which of the following is the synonym of the word “PLUTOCRAT”?
(A) Magnate
(B) Priest
(C) Judge
(D) Astronaut
Answer: (A)
6. Which of the following is the synonym of the word “BULWARK”?
(A) Conundrum
(B) Festival
(C) Rampart
(D) Confuse
Answer: (C)
NUMERICAL REASONING
1. An equilateral triangle of side √3cm is inscribed in a circle. Find the radius of the circle.
A. 2/3 cm
B. 2 cm
C. 1 cm
D. 3 cm
Answer: C
Explanation
Since the inscribed triangle is equilateral, therefore the angles at all the points = 60°
Using the formula for inscribed circle,
2R = asinA=bsinB=csinC
where R = radius of the circle; a, b and c are the sides of the triangle.
⇒ 2R = 3√sin60
2R = 3√3√2
2R = 2
R = 1cm
2. 3y = 4x – 1 and Ky = x + 3 are equations of two straight lines. If the two lines are perpendicular to each other, find K.
A. -4/3
B. -3/4
C. 3/4
D. 4/3
Answer: A
Explanation
Grad of 3y = 4x – 1
y = 4x/3 – 1/3
Grad = 4/3
Grad of Ky = x + 3
y = x/k + 3/4
Grad = 1/k
Since two lines are perpendicular,
1/k = -3/4
-3k = 4
k = -4/3
3. if P and Q are fixed points and X is a point which moves so that XP = XQ, the locus of X is
A. A straight line
B. a circle
C. the bisector of angle PXQ
D. the perpendicular bisector of PQ
Answer: D
4. In a regular polygon, each interior angle doubles its corresponding exterior angle. Find the number of sides of the polygon.
A. 8
B. 6
C. 4
D. 3
Answer: B
Explanation
2x + x = 180°, => 3x = 180°, and thus x = 60°
Each exterior angle = 60° but size of ext. angle = 360°/n
Therefore 60° = 360°/n
n = 360°/60° = 6 sides
5. A predator moves in a circle of radius √2 centre (0,0), while a prey moves along the line y = x. If 0 ≤ x ≤ 2, at which point(s) will they meet?
A. (1,1) only
B. (1,1) and (1,2)
C. (0,0) and (1,1)
D. (√2,√2) only
Answer: Option A
Explanation
x2 + y2 = (√2)2
x2 + y2 = 2
but y = x
Thus; x2 + x2 = 2
2×2 = 2
x2 = + or – 1
But x2 + y2 = 2
12 + y2 = 2
1 + y2 = 2
y2 = 2 – 1
y2 = 1
y = + or – 1
Thus point (x,y) = (1,1) only.


